Question

The perimeter of a isosceles triangle is 117/14 .if its unequal side measures 8/3 cm ,find the measure of its equal sides.

Answer 1

Answer:

5.7cm and 2.85cm

Step-by-step explanation:

_perimeter -117/14= 8.3cm

_the unequal side= 8/3= 2.6cm

>8.3-2.6=5.7(one side)

5.7/2=2.85

Final Respuesta ==(5.7 y 2.85) cm

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Answer 2

Given : The perimeter of a isosceles triangle is 117/14 . its unequal side measures 8/3 cm.

To find : Measure of equal sides.

Solution :

Perimeter of isosceles triangle  = $\frac{117}{14}$

Length of unequal side =$\frac{8}{3}$

Perimeter of triangle = Sum of all the sides = A+B+C

Let be length of equal sides be x.

So the equation will be :

⇒x+x+$\frac{8}{3\\}$ = $\frac{117}{14}$

Taking LCM on the left hand side.

⇒ $\frac{3x+3x+8}{3}$ =$\frac{117}{14}$

⇒ $\frac{6x+8}{3}$ =$\frac{117}{14}$

On cross multiplying the equation.

⇒14(6x+8) = 117×13

⇒84x+112 = 351

⇒84x = 351-112

⇒84x = 239

⇒x = $\frac{239}{84}$ = 2.84cm

So the measure of each equal side is 2.84cm.