Math, asked by MANIAC1, 11 months ago

the perimeter of a isosceles triangle is 32cm.The ratio of the equal side to its base is 3:2.find the length of the smallest altitude.​

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Answered by Anonymous
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\huge{\bigstar}}\boxed{\huge{\mathfrak{\red{Answer}}}}\huge{\bigstar}}

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Let ABC an isosceles ∆ with perimeter 32 cm .

Ratio of equal side to it's base is 3:2 .

Let sides of ∆ be,

AB = BC = 3x

AC = 2x

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Perimeter of ∆ → 32 cm

AB + BC + AC → 32 cm

3x + 3x + 2x → 32 cm

8x → 32 cm

x \longrightarrow \frac{32}{8}

\boxed{x \longrightarrow 4}

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\mathfrak{Length\:of\:smallest\:side \longrightarrow AC \rightarrow 8\:cm}

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