THE perimeter of a parallelogram given ABCD=40,AB=3x,BC=2x,CD=2(y+1)cm.find the value of x and y
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First of all, AD=BC, so BC also is 2x.
Secondly, AB=CD, so 3x=2y+2. If you solve for 2y, 2y=3x-2
Thirdly, Perimeter = Sum of four sides
2x+3x+2x+2y+2 = 40
Simplify:
7x+2y+2=40
Substitute 2y=3x+2:
7x + 3x-2+2=40
10x=40
x=4
2y=3x-2
2y=3*4-2
2y=10
y=5
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