Math, asked by krishna27099, 10 months ago

The perimeter of a parallelogram is 102 cm. If one side is greater than the other by 9 cm, find the lengths of all the sides of the parallelogram The perimeter of a parallelogram is 102 cm. If one side is greater than the other by 9 cm, find the lengths of all the sides of the parallelogram​

Answers

Answered by jatinkhetan05122005
5

Step-by-step explanation:

perimeter of IIgm = 102

2(l+b)=102

2(x+x+9)=102

2(2x+9)=102

2x+9=102/2

2x=51-9

x=42/2

x=21

one side = 21

second side = 21+9=30

Answered by RvChaudharY50
19

\color {red}\huge\bold\star\underline\mathcal{Question:-}

find the lengths of all the sides of the parallelogram.. ?

\bold{\boxed{\huge{\boxed{\orange{\small{\boxed{\huge{\red{\bold{\:Answer}}}}}}}}}}

let \: one \: side \: of \: llgm \:  = x \: cm

than \: other \: side \:  = (x + 9) \: cm

Now,

we \: know \: that \: opposite \: sides \: of \: llgm \: are \: equal \: in \: length \: ..

so,

2(x + x + 9) = 102

(2x + 9) \:  = 51

2x \:  = 42 \\  \\ x \:  \: =   \frac{42}{2}  \\  \\  \\ x \:  \:  \:  \: =  21cm

so,

other \: side \:  = (21 + 9) = 30cm

so \: all \: sides \: of \: llgm \: are \:  \\  \\ {(21) \: (30) \: (21) \: (30)}

\huge\blue{</strong><strong>THANKS</strong><strong>}

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