Question

The perimeter of a parallelogram is 102 cm. If one side is greater than the other by 9 cm, find the lengths of all the sides of the parallelogram The perimeter of a parallelogram is 102 cm. If one side is greater than the other by 9 cm, find the lengths of all the sides of the parallelogram​

Answer 1

Step-by-step explanation:

perimeter of IIgm = 102

2(l+b)=102

2(x+x+9)=102

2(2x+9)=102

2x+9=102/2

2x=51-9

x=42/2

x=21

one side = 21

second side = 21+9=30

Answer 2

$\color {red}\huge\bold\star\underline\mathcal{Question:-}$

find the lengths of all the sides of the parallelogram.. ?

$\bold{\boxed{\huge{\boxed{\orange{\small{\boxed{\huge{\red{\bold{\:Answer}}}}}}}}}}$

$let \: one \: side \: of \: llgm \: = x \: cm$

$than \: other \: side \: = (x + 9) \: cm$

Now,

$we \: know \: that \: opposite \: sides \: of \: llgm \: are \: equal \: in \: length \: ..$

so,

$2(x + x + 9) = 102$

$(2x + 9) \: = 51$

$2x \: = 42 \\ \\ x \: \: = \frac{42}{2} \\ \\ \\ x \: \: \: \: = 21cm$

so,

$other \: side \: = (21 + 9) = 30cm$

$so \: all \: sides \: of \: llgm \: are \: \\ \\ {(21) \: (30) \: (21) \: (30)}$

$\huge\blue{</strong><strong>THANKS</strong><strong>}$