Question

the perimeter of a parallelogram is 120 if difference the adjacent side of parallelogram is 10 find the adjacent sides of the parallelogram​

Answer 1

If the difference in the adjacent side of the parallelogram is 10 and the perimeter is 120 then the adjacent sides of the parallelogram are 35 and 25.

Step-by-step explanation:

The perimeter of the parallelogram is given as = 120

Let the adjacent sides of the parallelogram be denoted as “a” and “b”.

The formula of the perimeter of a parallelogram is given by

Perimeter = 2[a+b]

By substituting the given value in the formula, we get

120 = 2[a+b]

⇒ [a+b] = $\frac{120}{3}$

⇒ a + b = 60 ……. (i)

It is also given that the difference between the adjacent sides of the parallelogram is 10 i.e.,

a – b = 10 ….. (ii)

Now, adding eq. (i) & (ii), we get

a + b = 60

a – b = 10

+  +      +

----------------

2a = 70

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∴ a = $\frac{70}{2}$ = 35

Substituting a = 35 in eq. (ii), we get

a – b = 10

⇒ b = 35 – 10 = 25

Thus, the adjacent sides of the parallelogram are 35 and 25 respectively.

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