The perimeter of a parallelogram is 140 cm.If one of the side is longer than the other by 10 cm, find the length of each of it's side
Answers
Answered by
313
Let the first side is x
then the second side become (x+10)
According to the question
2(x+x+10) =140
2(2x+10)=140
2x+10=70
2x=70-10
2x=60
x=30
first side=x=30cm
second side=x+10=40cm
then the second side become (x+10)
According to the question
2(x+x+10) =140
2(2x+10)=140
2x+10=70
2x=70-10
2x=60
x=30
first side=x=30cm
second side=x+10=40cm
yahyaahmad:
thank you so much
Answered by
115
hello users ...
solution:-
we have given that:
one of the side is longer than the other by 10 cm.
=> let the one side of parallelogram is = x
and
second = ( x + 10 )
now
perimeter = 2 * ( a +b)
where a and b are two non parallel sides .
=> 140 = 2 × [ x + (x +10) ]
=> 140 = 2× (2x + 10 )
=> 70 = 2x +10
=> 2x = 60
=> x = 30
Hence
one side of parallelogram is = 30 cm
and
other side = 30 + 10 = 40 cm
@ hope it helps :)
solution:-
we have given that:
one of the side is longer than the other by 10 cm.
=> let the one side of parallelogram is = x
and
second = ( x + 10 )
now
perimeter = 2 * ( a +b)
where a and b are two non parallel sides .
=> 140 = 2 × [ x + (x +10) ]
=> 140 = 2× (2x + 10 )
=> 70 = 2x +10
=> 2x = 60
=> x = 30
Hence
one side of parallelogram is = 30 cm
and
other side = 30 + 10 = 40 cm
@ hope it helps :)
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