The perimeter of a parallelogram is 150 cm. One of its side is greater than the other side by 25 cm find the length of all sidesa.
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Given, perimeter of parallelogram = 150cm
As we know that opposite sides of llgm are equal.
so, let two opposite ll sides be x cm
and other two ll sides be 25+x cm
so. sum of all sides=150cm
x+x+25+x+25+x=150cm
4x+50=150
4x=100
x=25 cm
so,first two sides of ll gm=x =25cm
and other two ll sides= 25+x=25+25=50cm
As we know that opposite sides of llgm are equal.
so, let two opposite ll sides be x cm
and other two ll sides be 25+x cm
so. sum of all sides=150cm
x+x+25+x+25+x=150cm
4x+50=150
4x=100
x=25 cm
so,first two sides of ll gm=x =25cm
and other two ll sides= 25+x=25+25=50cm
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Solution :-
First of all we need to know that what is parallelogram ?
» Parallelogram is a quadrilateral in which opposite sides are parallel to each other .
Let us see some Properties of Parallelogram :-
▪️ Opposite sides are congruent to each other i.e they have same length.
▪️ Opposite angles are congruent to each other .
▪️ Diagonals bisect each other .
▪️ Each of the Diagonals divide the parallelogram into two congruent triangle.
Now solving the problem :-
Given that
Perimeter = 150 cm
One side is greater than other by 25 cm
Now let the smaller side be x cm
Then other side = (x + 25) cm
Now from the property of the parallelogram :-
Opposite sides are equal
→ Two of the sides = 2x
→ Two of the sides = 2(x + 25)
Now by solving it further
→ 2x + 2(x + 25) = 150
→ 2x + 2x + 50 = 150
→ 4x = 150 - 50
→ 4x = 100
→ x = 25 cm
and other side = x + 25
= 50 cm
Lengths of all sides of parallelogram are 50cm , 25cm , 50cm and 25cm.
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