Math, asked by renugakurinji, 3 days ago

The perimeter of a parallelogram is 6xy - 3yz + 7xz If one of its sides is xy+4yz-3xz, then find the other side.​

Answers

Answered by nomanchaush96
0

Answer:

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Answered by parthisop
1
  • Given thta
  • Given thtaPerimeter of a parallelogram =140 cm
  • Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cm
  • Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,
  • Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cm
  • Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know that
  • Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm
  • Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140
  • Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=70
  • Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−15
  • Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−152x=55
  • Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−152x=55x=
  • Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−152x=55x= 2
  • Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−152x=55x= 255
  • Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−152x=55x= 255
  • Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−152x=55x= 255
  • Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−152x=55x= 255 x=27.5 cm
  • Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−152x=55x= 255 x=27.5 cm One side =27.5 cm
  • Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−152x=55x= 255 x=27.5 cm One side =27.5 cmlong side =27.5+15
  • Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−152x=55x= 255 x=27.5 cm One side =27.5 cmlong side =27.5+15long side =42.5 cm
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