the perimeter of a parallelogram is 88 cm and one of its adjacent side is longer than the other by 10 cm. find the length of each of its side
Answers
Answered by
9
Answer: Perimeter if parallelogram=2(l+b)
There p=88
Let breadth be x
Therefore,length=x+10
Substituting the values
88=2(x+(x+10))
88=2(2x+10)
88=4x+20
88-20=4x
684x
x=68/4
x=17
Therefore breadth is 17 and length is 27
Hope it helps
There p=88
Let breadth be x
Therefore,length=x+10
Substituting the values
88=2(x+(x+10))
88=2(2x+10)
88=4x+20
88-20=4x
684x
x=68/4
x=17
Therefore breadth is 17 and length is 27
Hope it helps
Answered by
5
Answer:
Step-by-step explanation:
As we know perimeter of parallelogram is 2
and let the breadth be x
so , perimeter = 88 cm
length = x + 10
88 = 2 ( x + 10 ) [ dont add perimeter 2 and 88 ]
88 = 2 ( 2x + 10 )
88 = 4x + 20
88 = 20 = 4
Add all this no : 4 + 4 + 20 + 10 + 10 + 20 = 68
x = 68 ÷ 4
= 17
so , length = 17 and breadth = 27
so the answer is 27 , 17 , 27 , 17
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