Question

The perimeter of a parallelogram is 88 cm. The length of one of its sides is
4 cm more than that of its adjacent side. What is the length of the longer
side of the parallelogram?
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Answer 1

$\huge{\mathfrak{\underline{\underline{Solution:-}}}}$

$\sf{Perimeter\:of\:a\:parellelogram=2(l+b)=88\:cm}$

Let the length be x cm and the breadth be (x + 4) cm.

$\sf{Therefore,}$

$\sf{2(x+x+4)=88}$

$\sf{2(2x+4)=88}$

$\sf{4x+8=88}$

$\sf{x=\frac{88-8}{4}}$

$\sf{x=20}$

So, the length of the longer side would be 24 cm.