The perimeter of a park is 240 m. The length of the park is 40 m more than that of the breadth. By writting system.
Answers
Step-by-step explanation:
let ,breadth equals to x
length=x+40
perimeter=2(x+x+40)
2(2x+40)=240
or,4x+80=240
or,4x=160
or,x=40
so the breadth=40m
and the length=80m
- The Perimeter of a Park is 240 m. The Length of the Park is 40 m more than that of the Breadth
- Perimeter of a Park = 240 m
- The Length of the Park is 40 m more than that of the Breadth
- Length and Breadth of Park
- Breadth of Park = 40 m
- Length of Park = 80 m
Perimeter of a Park = 240 m
Perimeter of Rectangle = 2 × (Length + Breadth)
⇒ 2 × (Length + Breadth) = 240 m
Substitute The Values of Length and Breadth
⇒ 2 × [(x + 40 m) + x)] = 240 m
⇒ 2 × [x + 40 m + x)] = 240 m
⇒ 2 × [2x + 40 m] = 240 m
Apply Distributive Law : a × (b + c) = ab + ac
⇒ 4x + 80 m = 240 m
Subtract 80 m from Both Sides
⇒ 4x + 80 m - 80 m = 240 m - 80 m
⇒ 4x = 160 m
Dividing Both Sides By 4
⇒ 4x/4 = 160 m/4
⇒ x = 40 m
From This We get :
- Breadth = x = 40 m
- Length = x + 40 m = 40 m + 40 m = 80 m
Perimeter of Rectangle = 2 × (Length + Breadth)
Substitute The Values of Length and Breadth
⇒ Perimeter of Rectangle = 2 × (80 m + 40 m)
Given Perimeter of a Park = 240 m
⇒ 240 m = 2 × (80 m + 40 m)
⇒ 240 m = 2 × (120 m)
⇒ 240 m = 240 m
- As Both Sides are Equal, Our Answer is Correct
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