Question

the perimeter of a parrellogram is 280cm one of its sides is less than the other by 10 find the lengths of the sides

Answer 1

Perimeter=280 cm

Let one of the sides(the length) be x, hence the other(breadth) becomes x-10

Perimeter=2(l+b)
280 =2[x+(x-10)]
280 =2(2x-10)
280 =4x-20
280+20=4x
300=4x
x=300/4
x=75

Hence l=75
b=75-10
=65

Answer 2

Perimeter of a parallelogram:2(l+b)=280
b=l-10,
2(l+l-10)=280
2l-10=140,
l=75,b=l-10=75-10=65,
sides=75,65...