the perimeter of a protector is 72cm.Calculate the area of the protector.
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Answered by
7
Hi ,
We know that shape of a protracter
is semicircle,
Let radius of the semicircle = r cm
Perimeter of the protracter = 72 cm
πr + 2r = 72
r ( π + 2 ) = 72
r ( 22/7 + 2 ) = 72
r ( 22 + 14 )/7 = 72
( 36/7 )r = 72
r = ( 72 × 7 )/36
r = 14 cm.
Therefore ,
Area of the protracter = area of the
but semicircle
= ( 22/7 ) (14)²/ 2
= ( 22 × 14 × 14 )/( 7 × 2 )
= 22 × 14
= 308 cm²
I hope this helps you.
:)
We know that shape of a protracter
is semicircle,
Let radius of the semicircle = r cm
Perimeter of the protracter = 72 cm
πr + 2r = 72
r ( π + 2 ) = 72
r ( 22/7 + 2 ) = 72
r ( 22 + 14 )/7 = 72
( 36/7 )r = 72
r = ( 72 × 7 )/36
r = 14 cm.
Therefore ,
Area of the protracter = area of the
but semicircle
= ( 22/7 ) (14)²/ 2
= ( 22 × 14 × 14 )/( 7 × 2 )
= 22 × 14
= 308 cm²
I hope this helps you.
:)
Answered by
0
Answer:
308 cm2
Step-by-step explanation:
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