The perimeter of a quadrant of a circle is 71.4 cm find its area
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Perimeter of a quadrant of a circle = 71.4cm
Let its radius be r
ATP
2πr/4 = 71.4
= r = 71.4×4×7/22×1/2
= r = 45.4363636
Area = πr^2
= 22/7×45.4363636×45.4363636
= 6,488.31272 cm^
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