The perimeter of a quadrant of a circle of radius 7 2 cm is (A) 7.5 cm (B) 12.5 cm (C) 7.5 cm (D) 3.5 cm
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Answer:
Radius of quadrant = 7/2 cm
Perimeter of quadrant = length of arc +(2× radius)
=(1/4×2πr)+2×7/2
=(1/4 ×2×22 /7 ×7/2 )+7
= 11/7 +7
=5.5+7
=12.5 cm
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