Question

the perimeter of a recantagle is 52cm.How long is each side if the width is 2 cm more than one-third of the length

Answer 1

Hope u like my process
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=> Let the length (l) be x cm

=> Breadth = Width =b
$= \underline{\blue{\frac{x}{3} + 2 \: \: \: cm}}$
=> Perimeter = 2(l+ b) cm = 52 cm

According to the problem.
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$= > 2(l + b) = 52 \\ \\ = > \blue{2(x + \frac{x}{3} + 2) } = \blue{52} \\ \\ = > \blue{x + \frac{x}{3} + 2} = \blue{\frac{52}{2} } = \blue{ 26} \\ \\ = > \blue{\frac{4x}{3}} = \blue{ 26 - 2} = \blue{24} \\ \\ = > \boxed{ \bf \: x = \blue{\frac{24 \times 3}{4}} = \underline{\green{18 \: \: cm}}}$

Thus the length is 18 cm

Breadth or width = 18/3 + 2 = 6 +2 =8cm
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