Question

The perimeter of a rectange is 32 cm its breadth is 5 cm find its length? How to do the working

Answer 1

perimeter of rectangle=32cm
length=x
breadth=5cm
perimeter of rectangle =2(l+b)
32cm=2(x+5)
2x+10=32
2x=22
x=11
length of rectangle is 11cm

Answer 2

Answer:

The length is 11 cm.

Step-by-step explanation:

Given :

Perimeter of the rectangle = 32 cm

Breadth = 5 cm

To find :

Its Length

Solution :

Let the Length be as y

★ Perimeter = 2(Length + Breadth)

⇒ 32 = 2(y + 5)

⇒ 32 = 2y + 10

⇒ 2y = 32 - 10

⇒ 2y = 22

⇒ y = $\tt{\dfrac{22}{2}}$

⇒ y = 11

Length of the rectangle = 11 cm

$\therefore$ The length is 11 cm.

$\rule{300}{1.5}$

Verification :

⇒ 32 = 2(11 + 5)

⇒ 32 = 22 + 10

⇒ 32 = 32

⇒ LHS = RHS

$\therefore$ The length is 11 cm.