Question

The Perimeter of a rectangle
192cm. If its length is twice is
width. Find its length and width.​

Answer 1

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The area of a rectangle is 192cm^(2) and the dimension is 56cm. What is the length of the rectangle?

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9 Answers



Audley Willacey, B.Sc. Mechanical Engineering, University of the West Indies, St. Augustine (1976)

Answered 4 February 2020

Originally Answered: The area of a rectangle is 192cm^(2) and the perimeter is 56cm. What is the length of the rectangle?

Area of rectangle = lw

Perimeter of rectangle = 2(l+w) = 2l + 2w

lw = 192 ……(i)

2l + 2w = 56 ===> l+w = 28 ……(ii)

From (ii) : w = (28 -l)

Subst w in (i) : l(28-l) = 192

28l - l^2 = 192

l^2 - 28l + 192 = 0

(l - 16)(l - 12) = 0

l = 16 or 12

w = 28 - l = 12 or 16.

Length of recrangle = 16 cm. [Width = 12 cm]

Answer 2

Answer:

$perimeter \: of \: rectangle = 2(l + b) \\ let \: b \: be \: x \\ then \: l = 2x\\ 2(2x + x) = 192 \\ 2 \times 3x = 192 \\ 6x = 192 \\ x = 192 \div 6 \\ x = 32 \\ breadth \: = 32 \\ then \: length \: = 2x \\ = 2 \times 32 = 64$