the perimeter of a rectangle 56 cm and length of a rectangle 17 cm find the breadth of the rectangle
Answers
Answer:
In a rectangle we know that two opposite sides are equal. So, PQ = SR and PS = QR
Step-by-step explanation:
If PS = l and PQ = b
Perimeter of a Rectangle
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Perimeter of the rectangle = PQ + QR + RS + SP
= b +l + b + l
= 2b +2l
Again,
ABCD is a rectangle. We know that the opposite sides of a rectangle are equal.
Perimeter of a Rectangle
AB = CD = 5 cm and BC = AD = 3 cm
So, the perimeter of the rectangle ABCD = AB + BC + CD + AD = 5 cm + 3 cm + 5 cm + 3 cm = 16 cm
It can be written as 5 cm + 5 cm + 3 cm + 3 cm
= (2 × 5) cm + (2 × 3) cm
= 2 (5 + 3) cm
= 2 × 8 cm
= 16 cm
We add length and breadth twice to find the perimeter of a rectangle.
Perimeter of a rectangle = 2 (length + breadth)
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Answer:
Breadth = 11 cm
Step-by-step explanation:
Perimeter = 56 cm
Length = 17 cm
Breadth = x
Perimeter of a rectangle = 2(l + b)
56 cm = 2(17 + x)
56 = 34 + 2x
56 - 34 = 2x
22 = 2x
22/2 = x
11 = x