The perimeter of a rectangle and a square are 160 m. each. The area of the rectangle is less than
that of the square by 100 sq m. The length of the rectangle is ?
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so according to conditions
perimeter of rectangle = perimeter of square
2( l +b ) = 4 a = 160
a = 160 / 4 = 40 m
2(l +b ) = 160
l +b = 80 m
Now area of rectangle = Area of square - 100
l × b = a² - 100
l ×b = (40)² - 100
l × b = 1600 - 100
l×b =1500
l +b = 80
solving these both equations
length = 50m and breadth = 30m
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