The perimeter of a rectangle and a square are same. The length and breadth of the rectangle are 50cm and 34cm respectively. Find which figure has greater area and by how much ??
it's Isha
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Answers
Answer:
ar of square is bigger by 64cm^2
Step-by-step explanation:
perimeter of ractangle=perimeter of square
2(l+b)=4(side)
l+b=2(side)
50+34=2(side)
84/2=side
42cm=side
so area of rectangle is l*b
ar of rectangle=50*34
ar=1700cm^2
ar of square is side*side
ar of square=42*42
ar of square=1764cm^2
ar of square - ar of rectangle
1764-1700
64cm^2
ar of square is bigger than ar of rectangle by 64 cm^2
≡hey Isha di....
≡ hru
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≡ here is your answer....
Given - The perimeter of Rectangle and square is same.
L = 50cm and B = 34cm
To find - The figure which has a greater area and by how much
Calculation -
Perimeter of Rectangle = 2(l + b)
2 ( 50 + 34)
100 + 68
= 168 cm
Therefore Perimeter of square will be also 168 cm.
Perimeter of square = 4a or sum of all sides.
Let the side be x
Therefore,
4x = 168
x = 168/4
= 42
Therefore,
One Side of square = 42cm
=========================================
Now,
Calculating the area.
Area of rectangle = Length × breadth
= 50 × 34
= 1700cm²
Area of square = (Side)²
= (42)²
= 1764 cm²
Therefore Square has larger area by -
1764 - 1700 = 64cm²