the perimeter of a rectangle and Square are same. if the length and breadth of rectangle are 25 cm and 17 cm respectively, find which figure has greater area and how much
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according to question
perimeter of a rectangle is the same as that of the square
so
2 (l+b)=4×s
2×(25+17)=4×s
2×42=4×s
4×s=84
s=84/4=21
now
area of the square =s×s=21×21
=441 cm sq
area of the rectangle =l×b=25×17
=425 cm sq.
so from here we can conclude that the square has a greater area
difference =441-425=16 cm sq.
here is ur answer HOPE IT HELPS
⛤⛤⛤⛤⛤⛤
according to question
perimeter of a rectangle is the same as that of the square
so
2 (l+b)=4×s
2×(25+17)=4×s
2×42=4×s
4×s=84
s=84/4=21
now
area of the square =s×s=21×21
=441 cm sq
area of the rectangle =l×b=25×17
=425 cm sq.
so from here we can conclude that the square has a greater area
difference =441-425=16 cm sq.
Answered by
2
Answer
NO THE PERIMETER OF RECTANGLE ARE NOT SAME.
BUT BOTH ARE QUADRILATERALS[4SIDED POLYGON]
RECTANGLE HAVE LENGTH AND BREADTHREA OF RECTANGLE
BUT ALL THE SIDES OF A SQAUARE ARE EQUAL
Step-by-step explanation:
AREA OF RECTANGLE=length*breadth
here length=25cm
breadth=17cm
Therefore Area=l*b
25cm*17cm=425 sqcm
but we could not find the area of a square without its one side is not given
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