Question

the perimeter of a rectangle field is 628m the length osf the field exceeds its width by 6m find the dimension ​

Answer 1

Answer:

The perimeter of a rectangular field is 628m. The length of the field exceeds its width by 6m. What are the dimensions?

The perimeter of a rectangular field is 628m.

Or L+B = 628/2 = 314 m

L+L-6_ = 314, or 2L = 320 or L = 160 and so B = 314–160 = 154 m.

The length of the field = 160 m and the width = 154 m.

Answer 2

Answer:

Perimeter pf rectangle = 2(l+b)

Step-by-step explanation:

let width = x meter

length = x + 6 meter

Perimeter of rectangular field = 628 m

2(l+b) = 628

2(x+6+x) = 628

2(2x+6) = 628

2x+6 = 628/2

2x+6 = 314

2x = 314 - 6

2x = 308

x = 308 / 2

x = 154 m

width of rectangular field = 154 m

length of rectangular field = 154 + 6 = 160 m