Question

The perimeter of a rectangle h 52 cm. If it width is 2 cm more
than one-third of its length, find the dimensions of rectangle
​

Answer 1

Answer:

The length of the Rectangle is 18 cm and breadth is 8 cm.

Step-by-step explanation:

We are given,

Perimeter = 52 cm

also,

b = (1/3)l + 2

where 'b' stands for breadth and 'l' stands for length.

Now,

b = (1/3)l + 2

b - 2 = (l/3)

l = 3(b - 2)

l = 3b - 6 ------ 1

Now,

We know that,

Perimeter of a rectangle = 2(l + b)

P = 52 cm

∴ 52 = 2(l + b)

From eq.1 we get,

52 = 2(3b - 6 + b)

52 = 2(4b - 6)

52 = 8b - 12

8b = 52 + 12

8b = 64

b = 64/8

b = 8 cm

Now, from eq.1 we get,

l = 3(8) - 6

l = 24 - 6

l = 18 cm

Thus, the length of the rectangle is 18 cm and breadth is 8 cm.

We can also check this,

b = (l/3) + 2

8 = (18/3) + 2

8 = 6 + 2

8 = 8

Thus, it is correct

Perimeter = 2(l + b)

52 = 2(18 + 8)

52 = 2(26)

52 = 52

Thus, it is correct

Hope it helped and believing understood it........All the best