Question

the perimeter of a rectangle is 10 M and its area is 5 1/4 square metres. what are the length of its side​

Answer 1

Answer:

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Let x and y be the length and breadth of this rectangle. So 2x + 2y = 10 and xy = 5.25.

This is known as 2 equations with 2 unknowns. Let's solve for x. 2x= 10–2y. So x = 5-y. Just substitute and we have (5-y)y= 5.25.

5y-y^2=5.25. Rewritten as y^2–5y+5.25=0

Use quadratic equation -b+/- sqroot(b^2–4ac) all over 2a.

Hence x and y are 3.5 and 1.5 meters, respectively.

Answer 2

Answer:

I don't know the answer I will help you next time