Question

the perimeter of a rectangle is 10 metres and its area is 5 1/4 for square metres what are the length of its side? ​

Answer 1

Answer:

x = 21/5,  y = 4/5

Step-by-step explanation:

2(x+y) = 10

xy = 5/1/4

x+y = 5

x = (21y)/4

(21y)/4 + y = 5

21y + 4y = 20

25y = 20

y = 4/5

x = 21/5

Answer 2

Answer :-

Taking the length of the sides as x meters and y meters, perimeter is 2(x+y) meters and area is xy

square meters.

$\bf \: x + y = 5$

$\bf \: xy = 5 \frac{1}{4}$

next,

Recall that, ⤵⤵️⤵️

$\bf \: (x + y) {}^{2} - (x - y) {}^{2} = 4xy$

We can write this as, ⤵️⤵️

$\bf \: (x - y) {}^{2} = (x + y) {}^{2} - 4xy$

In problem

$\bf \: (x - y) {}^{2} = {5}^{2} -(4 \times 5 \frac{1}{4} = 25 - 21 = 4$

This gives x - y = 2 . Together with x + y = 5

We can find ⤵️

$\bf \: x = 3 \frac{1}{2} . \: \: y = 1 \frac{1}{2}$

Sides of rectangles are ⤵️⤵️⤵️

$\bf \: 3 \frac{1}{2} m \: \: and \: \: 1 \frac{1}{2} m$