Question

The perimeter of a rectangle is 100 metre and it's length is 8 metre more than twice the breadth. What are it's length and breadth?​

Answer 1

Answer:

let breadth be x

length=x+8

perimeter=2(l+b)

=2(x+x+8)

atq

2(x+x+8)=100m

2(2x+8)=100

4x+16=100

4x=84

x=84/4

x=21

length=21+8=29

breadth=21

hope it helps you

Answer 2

Answer:

let the length ( l ) be ==> (8 + x) m

let the breadth ( b ) be ==> x

p = 100 {given}

p = 2 ( l + b )

100 = 2(8 + x+x) m

100 = 16 + 2x + 2x

4x = 100 - 16 = 84

$x = \frac{84}{4} = 21$

therefore,

l = (8+m) = 8 + 21 = 29m

b = x = 21 m

$\rm \: checking = = >$

p = 2 ( l + b)

p = 2 ( 29 + 21 )

p = 2 ( 50)

p = 200

hence, proved