Question

the perimeter of a rectangle is 1050m and the length is 225m. find the breadth of the rectangle

Answer 1

perimeter=2(l+b)
1050m =2(225+b)
1050m =450+2b
1050-450m=2b
600m=2b
600/2=b
300m=b


verification

perimeter=2(l+b)
=2(225+300)m
=2(525)m
=1050m

Answer 2

Perimeter of rectangle = 2 (l+b)
According to the condition,
Breadth of rectangle = (1050/2) -225 = 525 -225 = 300 m . Ans