Question

The perimeter of a rectangle is 110 metres and its length is 4 M more than the its breadth. Find its length and breadth

Answer 1

Lengh = 24 m

Lengh = 24 mBreadth = 28 m

Step-by-step explanation:

let the breadth be X

length = X+4

perimeter of a rectangle = 2(L+B)

BTP,

=> 2(X+X+4)=110

=> 2(2X+4)=110

=> 4X+8=110

=> 4X=110-8

=> 4X=112

=> X=112÷4

=> X=28

Breadth = 28 m

Length = 28-4 m

= 24 m

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Answer 2

Solution:

Perimeter of rectangle = 110 m

Let the breadth = x m

Then, the length = x + 4 m

P = 2(l + b)

A/Q,

110 = 2(x + 4 + x)

Dividing both sides by 2

↬ 110/2 = x + 4 + 2

↬ 55 = x + 4 + x

↬ 55 = 2x + 4

↬ 2x + 4 = 55

↬ 2x = 55 - 4

↬ 2x = 51

↬ x = 51/2

↬ x = 25.5m

Therefore,

• Breadth = x = 25.5m

Length = x+4 = 25.5+4 = 29.4m

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