Question

the perimeter of a rectangle is 110m. find the dimensions if the length is 5m lesser than twice its breadth

Answer 1

Answer:

perimeter= 110= 2(l+b)

let breadth be b then

length = 2b - 5

solution-

110= 2(l+b)

110 = 2( 2b -5 +b)

110 = 2(3b-5)

110/2= 3b -5

55 = 3b -5

55+5 = 3b

60 = 3b

20 = b

Step-by-step explanation:

breadth= b = 20

length = 2b - 5 = 2x20 -5= 40 - 5 = 35

HOPE THIS HELPS U

Answer 2

Step-by-step explanation:

Let the width of rectangle=x

Hence, length=x+5

Perimeter=2(length+width)

110=2(x+5+x)

110=2(2x+5)

55=2x+5

2x=50

x=25

x+5=25+5=30

Hence, length=30m and width=25m Ans.