Question

The perimeter of a rectangle is 112cm and its breadth is x cm.
1) given that area of rectangle is 597cm. Formulate an equation in x and show that it reduces to x(square)-56x+597=0

Chapter name: Quadratic equations
Useful answers: brainliest.. rubish answers: report

Answer 1

Answer:

your required answer is below....

Step-by-step explanation:

Here,

the perimeter of a rectangle is 112cm and it's breadth is x cm.

and given that area of the rectangle is 597cm.

then,

let the length be y.

therefore,

$2(x + y) = 112$

$or \: \: y = 56 - x$

then, area of the triangle

$x \times(56 - x) = 597$

$or \: 56x - {x}^{2} = 597$

$or \: {x}^{2} - 56x + 597 = 0$

$hence \: proved$

thanks a lot.....