Question

The perimeter of a rectangle is 120cm. If the length is twice its breadth. Find area​

Answer 1

Answer :-

• The area of the rectangle is 800 cm² or 8 m².

Given :-

• The perimeter of a rectangle is 120 cm.
• The length is twice its breadth.

To find :-

• The area of the rectangle.

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Step-by-step explanation :-

Let the breadth be x.

Since the length is twice its breadth, therefore let the length be 2x.

The perimeter is 120 cm.

We know that :-

Perimeter of a rectangle = 2 (Length + Breadth).

Lets apply this formula.

Substituting the values, we get :-

$\bf{2 \: (2x + x) = Perimeter }$

$\bf \: 2 \: (2x + x) = 120 \: cm \: (Perimeter)$

$\bf \: 4x + 2x = 120 \: cm$

$\bf \: 6x = 120 \: cm$

$\bf \: x = \dfrac{120 \: cm}{6}$

$\bf \: x = 20 \: cm.$

Since x, that is, the breadth = 20 cm,

Therefore, the length = 2x = 2 × 20 cm = 40 cm.

Now, we have :-

Area of a rectangle = Length × Breadth.

Lets apply this formula.

Substituting the values, we get :-

Area = 40 cm × 20 cm = 800 cm² or 8 m².

So, Area = 800 cm² or 8 m².

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Answer 2

Given :

The twice of length is breadth

The perimeter of rectangle 120 cm

To find :

The area of rectangle

Solution :

Let the breadth of the rectangle is b cm.

So, the length of the rectangle is 2b cm.

We know that the perimeter of rectangle is

$=2 \: (l+b)$

Since, perimeter of rectangle is 120 cm.

Therefore,

$6 \: b=120$

$b=20 cm$

And

$l=40 cm$

So, the area of rectangle is

$=20×40=800 cm {}^{2}$

Hence, the length is 40 cm, breadth is 20 cm and area is 800 cm2.