Question

The perimeter of a rectangle is 120m. If the difference between the length and the breadth is
4m, what is the circumference of the largest circle that can be drawn inside the rectangle?
94154
2) 90
3) 110
4) 132
5) 88
​

Answer 1

Answer:

Step-by-step explanation:

l-b=4m ............eq 1

perimeter of a rectangle is 120m

=2(l+b)=120

l+b=60 ............eq 2. now equation 2+1

l+b=60

l-b=4

+-------------

2l-0=64

---------------

2l=64

l =32

now equation 1-2

l+b=60

l-b=4

-

-----------------

2b=56

b=23

now you can find circumference with this formula 2πr

Answer 2

Answer:

5) 88 m

Step-by-step explanation:

Let the breadth be x.

So, length is x+4.

P(rect)=2(l+b)

P(rect)=2*(x+x+4)

120=4x+8

4*(x+2)=120

x+2=30

x=breadth=28 m.

x+4=length=32 m.

Radius of greatest circle possible is the smaller side divided by 2.

So, r=28/2=14 m

P(circle)=2*π*r

P(circle)=44*14/7

P(circle)=44*2

P(circle)=88 m

Note: p(rect) means perimeter of the

rectangle.

P(circle) means circumference of

circle.