The perimeter of a rectangle is 128 m. If one of the adjacent sides is 10 m longer than the other, find the lengths of the sides.
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Answered by
1
Answer:
One side is 27 and 37
Step-by-step explanation:
- 2(l+b)=128 (given)
- l+b=128/2=64
- LET BREADTH BE 'X' then other side is 10 more than that .so
- LENGTH = X+10
- L+B
- X+X+10=64
- 2X+10=64
- 2X=64-10=54
- 2X=54
- X=54/2=27
- X=27(BREADTH)
- X+10=27+10=37(LENGTH)
- BREADTH =27
- LENGTH =37
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