Question

the perimeter of a rectangle is 12m its breath is 10m less then its lenght. find the dimensions of the rectangle

Answer 1

Question:

The perimeter of a rectangle is 12m its breath is 10m less then its lenght. Find the dimensions of the rectangle.

Answer:

Perimeter given for the quéstion is wrong .

Given:

➛The perimeter of a rectangle is 12m.

➛Breath is 10m less then its lenght.

To Find:

Dimensions of the rectangle i.e. length and breadth of the rectangle.

Solution:

let l and b be the length and breadth of the rectangle.

We are given ,

➛The perimeter of a rectangle is 12m.

➛Breath is 10m less then its lenght.

We know ,

perimeter of the rectangle :

2 ( length × breadth )

According to given condition

Breadth = ( length - 10 )

⛬ b = ( l - 10 )........... ( 1 )

now ,

perimeter of the rectangle : 12 m. ...........( given )

➡2× ( l + b ) = 12

➡2× [ l + ( l - 10 ) ] = 12

➡ 2l - 10 = 12 / 2

➡ 2l - 10 = 6

➡2l = 6 + 10

➡ 2l = 16

➡ l = 16 / 2

l = 8 m

put in equation ( 1 )

b = 8 - 10

b = - 2

which is negative value .

But dimensions can not be negative .

Hence the perimeter given is wrong.

Here perimeter of the rectangle should be atlest 24 m . to find the dimensions

Answer 2

Question:-

The perimeter of a rectangle is 12 metre it's breadth is 10 metre less then its length then find the dimension of the rectangle.

Given:-

★ The perimetre of a rectangle is 12 m.

★ The breadth is 10m less then the length.

To Find:-

Find the dimension of the rectangle.

Solution:-

Let l and b be length and breadth of the rectangle.

We know,

perimeter of the rectangle = 2(l × b)

A\Q,

Breadth =(length - 10)

b = l - 10 ........................... (1)

Now,

Perimeter of the rectangle = 12m

${\implies{\tt{ 2(l + b) = 12}}}$

${\implies{\tt{ 2 [ l (l- 10)] = 12}}}$

${\implies{\tt{ 2l - 10 = \frac{12}{2}}}}$

${\implies{\tt{ 2l - 10 = 6}}}$

${\implies{\tt{ 2l = 6 + 10}}}$

${\implies{\tt{ 2l= 16}}}$

${\implies{\tt{ l = \frac{16}{2}}}}$

${\implies{\tt{ l = \cancel\frac{16}{2} = 8}}}$

${\implies{\tt{ l = 8m}}}$

By putting in eq(1) we get,

${\implies{\tt{b = 8 - 10}}}$

${\implies{\tt{= -2}}}$

.

Hence, The value is in negative. But dimension cannot be negative. So your perimeter is wrong.