Question

The perimeter of a rectangle is 13 cm and its width is $2\frac{3}{4}\:cm$. Find its length.

Answer 1

Step-by-step explanation:

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Answer 2

QuestioN :

The perimeter of a rectangle is 13 cm and its width is $\sf 2\dfrac{3}{4} \:cm.$ Find its length.

GiveN :

• Perimeter of a rectangle = 13 cm

• Width = $\sf 2\dfrac{3}{4} \:cm.$

To FiNd :

• The length of the rectangle.

ANswer :

The length of the rectangle is $\sf 3\dfrac{3}{4} \:cm.$

SolutioN :

$\sf Assume \:the \:length \:of \:the \:rectangle \:to\: be\:x\:cm.$

$\sf The\: perimeter \:of \:the \:rectangle \:= 2 \times (length+width)$

$\sf \implies 2\times (x+2\dfrac{3}{4} )$

$\sf \implies 2\left[\begin{array}{ccc}\sf x+\dfrac{11}{4}\end{array}\right]$

$\sf \huge The\:perimeter \:is \:given\: to \:be \:13 \:cm.\: Therefore,$

$\sf \implies 2\left[\begin{array}{ccc} \sf x+\dfrac{11}{4}\end{array}\right] =13$

or,

$\sf \implies x+ \dfrac{11}{4}= \dfrac{13}{2}$    (Dividing both sides by 2)

or,

$\sf \implies x = \dfrac{13}{2}- \dfrac{11}{4}$

$\sf \implies \dfrac{26}{4}-\dfrac{11}{4}= \dfrac{15}{4}= 3\dfrac{3}{4}$

∴ Hence, The length of the rectangle is $\sf 3\dfrac{3}{4}\:cm.$

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