Question

the perimeter of a rectangle is 13 cm and its withs 2/3/4 cm find its ​

Answer 1

$\huge \mathfrak \red{answer}$

$\tt \blue{length}$

$\bf \boxed{ \frac{15}{4}}$

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$\bf \huge \underline{Question:}$

the perimeter of a rectangle is 13 cm and its withs 2/3/4 cm find its length

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$\bf \huge \underline{To \: find}$

length = ?

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step by step explanation:

Given:

• length of perimeter is 13cm

• breadth is 2 3/4

• length = ?

let length be l

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$\sf{⟹2 \frac{3}{4} = \frac{11}{4}}$

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Formula:

$\bf{ \boxed{ \underline{ \tt{perimeter \: of \: rectangle = 2(l + b) \: }}}}}}}$

$\rm{⟹13 = 2(l + b)}$

$\rm{⟹13 = 2(l+ \frac{11}{4}}$

$\rm{⟹13 = 2l + \frac{11}{2}}$

$\rm{⟹13 - \frac{11}{2} = 2l}$

$\rm{⟹26 - \frac{11}{2} = 21}$

$\rm{⟹ \frac{15}{2} = 2l}$

$\rm{⟹l = \frac{15}{2} \times 2}$

$\rm{⟹l = \frac{15}{4}}$

i hope it's help uh