Question

The perimeter of a rectangle is 13 m and its breath is 5 cm, find its length.​

Answer 1

Solution :

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large x cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large y cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

The perimeter of the rectangle is 13 m and it's breadth is 5cm.

We have to find the length.

Perimeter = 2(l+b)

>> 2(l + 5) = 1300

>> l+5 = 650

>> l = 645 cm.

Answer : The length of the rectangle is 645 cm or 6.45 m.

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Additional Information -

$begin{array}{|c|c|c|}\cline{1-3}\bf Shape&\bf Volume\ formula&\bf Surface\ area formula\\\cline{1-3}\sf Cube&\tt l^3}&\tt 6l^2\\\cline{1-3}\sf Cuboid&\tt lbh&\tt 2(lb+bh+lh)\\\cline{1-3}\sf Cylinder&\tt {\pi}r^2h&\tt 2\pi{r}(r+h)\\\cline{1-3}\sf Hollow\ cylinder&\tt \pi{h}(R^2-r^2)&\tt 2\pi{rh}+2\pi{Rh}+2\pi(R^2-r^2)\\\cline{1-3}\sf Cone&\tt 1/3\ \pi{r^2}h&\tt \pi{r}(r+s)\\\cline{1-3}\sf Sphere&\tt 4/3\ \pi{r}^3&\tt 4\pi{r}^2\\\cline{1-3}\sf Hemisphere&\tt 2/3\ \pi{r^3}&\tt 3\pi{r}^2\\\cline{1-3}\end{array}$

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Answer 2

Question :-

The perimeter of a rectangle is 13 m and its breath is 5 cm, find its length.

Answer :-

• Length =

Step by step explanation :-

We have given that,

• The perimeter of a rectangle is 13 m.
• its breath is 5 cm

We have to find,

• length

Using formula,

• Perimeter$\rm{_{(Rectangle)}}$ = 2(l + b)

Substituting all values,

⇒ 13 = 2(l + 5)

⇒ 13 = 2l + 10

⇒ 13 - 10 = 2l

⇒ 2l = 3

⇒ l = 3/2

⇒ l = 1.5m

Verification :-

⇒ 13 = 2(1.5 + 5)

⇒ 13 = 2(6.5)

⇒ 13 = 13

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