Question

the perimeter of a rectangle is 13cm and its width is 2.75 cm find its lenth in cm
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Answer 1

Given :

• Perimeter of Rectangle is 13 cm .
• Width of Rectangle is 2.75 cm .

To Find :

• Length of Rectangle .

Solution :

$\longmapsto\tt{Width=2.75\:cm}$

Using Formula :

$\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+w)}$

Putting Values :

$\longmapsto\tt{13=2(l+2.75)}$

$\longmapsto\tt{\cancel\dfrac{13}{2}=l+2.75}$

$\longmapsto\tt{6.5=l+2.75}$

$\longmapsto\tt{6-2.25=l}$

$\longmapsto\tt\bf{3.75\:cm=l}$

So , The Length of Rectangle is 3.75 cm ..

_______________________

• Area of Rectangle = length × width
• Perimeter of Rectangle = 2(l+w)
• Diagonal of Rectangle = √(l)² + (b)²
• Area of Square = (Side)²
• Perimeter of Square = 4 × Side
• Diagonal of Square = √2a

_______________________

Answer 2

Question :

To find length of a rectangle rectangle.

Solution :

• Given :

✰ Perimeter = 13 cm

✰ Width = 2.75 cm

• To find length :

We know that,

${\boxed{\bf{\underline{perimetre \:of \: rectangle \: = 2 \times (l + b) }}}}$

• l = Length
• b = breadth or width.

Let,

Length be x,

$: \implies\sf 2 \times( l + b)$

$: \implies\sf \: 2 \times (x + 2.75) = 13$

$: \implies\sf \: 2 \times x + 2 \times 2.75 = 13$

$: \implies\sf2x + 5.5 = 13$

$: \implies\sf2x = 13 - 5.5$

$: \implies\sf \: 2x = 7.5$

$: \implies\sf \: x = \frac{7.5}{2} = 3.75$

$\bf \: x = 3.75 \: cm$

$\bf \: length \: = 3.75 \: cm$

• Length of Rectangle is 3.75 cm

✰lets verify :

$\sf \: = > 2 \times (3.75 + 2.75)$

$= >\sf 2 \times 6.5$

$\sf = > 13 \: cm$

Hence Solved!!