Question

The perimeter of a rectangle is 16x²-6x²+ 12x+4. If one of it's side is 8x²+3x, find the other side??
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Answer 1

Answer:

$perimeter \: of \: rectangle = 2(l + b)$

if one of side is 8x²+3x and perimeter is 16x³-6x²+ 12x+4.

then,

$Perimeter \: of \: rectangle=16x^3−6x^2+12x+4$

$2(l+b)=16x^3−6x^2+12x+4$

$b=(8x^3−3x^2+6x+2)−(8x^2+3x)$

$=8x^3−3x^2+6x+2−8x^2−3x$

$=8x^3−11x^2+3x+2$

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