Math, asked by armanchowdhry7, 4 months ago

the perimeter of a rectangle is +16x³ -6x² +12x +4. If one of its sides is +8x² +3x find the other side.


please answer fast with full explanation.thank you.​

Answers

Answered by guditirukesh668
1

Answer:

8x^3-11x^2+3x+2

Step-by-step explanation:

perimeter of rectangle =2(l+b)

16x^3-6x^2+12x+4. =2(8x^2+3x+b)

2(8x^3-3x^2+6x+2). =2(8x^2+3x+b)

8x^3-3x^2+6x+2 =8x^2+3x+b

8x^3-3x^2-8x^2+6x-3x+2=b

b =8x^3-11x^2+3x+2

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