the perimeter of a rectangle is +16x³ -6x² +12x +4. If one of its sides is +8x² +3x find the other side.
please answer fast with full explanation.thank you.
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Answer:
8x^3-11x^2+3x+2
Step-by-step explanation:
perimeter of rectangle =2(l+b)
16x^3-6x^2+12x+4. =2(8x^2+3x+b)
2(8x^3-3x^2+6x+2). =2(8x^2+3x+b)
8x^3-3x^2+6x+2 =8x^2+3x+b
8x^3-3x^2-8x^2+6x-3x+2=b
b =8x^3-11x^2+3x+2
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