Question

the perimeter of a rectangle is 17 centimetre if each width is 15 by 4cm
then fiind its lenght​

Answer 1

Correct question: The perimeter of a rectangle is 17 cm. If its width is 15/4 cm. Find it's length.

Answer:

$\large{\underline{\boxed{\sf \dfrac{19}{4} \: cm}}}$

Step-by-step explanation:

Let the length of the rectangle be x cm.

According to the question ;

Perimeter of rectangle = 17 cm

⇒ 2(l + b) = 17

⇒ (x + 15/4) = 17/2

⇒ x = 17/2 - 15/4

⇒ x = 34 - 15/4

⇒ x = 19/4

Hence, the length of the rectangle is 19/4 cm.

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$\large{\underline{\underline{\mathfrak{\heartsuit \: Extra \: Information: \: \heartsuit}}}}$

A rectangle is a simple closed figure bounded by four line segments, where the opposite sides are equal. And each angle measures 90°.

Formulas related to rectangle -

• Area = length * breadth
• Perimeter = 2(l + b)

Answer 2

$\Huge{\boxed{Solution}}$

Given :

Perimeter of rectangle

= 17 cm

Each width is increased

by 15/4 cm.

===========================

To find :

Length of rectangle

===========================

Let us Take :

Length of rectangle

= 'x' cm.

===========================

According to the question

here we use formula

2 (Length + Breadth)

which is a perimeter of

rectangle.

===========================

Let us solve,

$\implies2\:(l+b) = Perimeter\\\\\\\implies2\:\bigg(x+\dfrac{15}{4}\bigg)=17\\\\\\\implies2\:\bigg(\dfrac{4x}{4}+\dfrac{15}{4}\bigg)=17$

$\\\\\\\implies\dfrac{4x}{4}+\dfrac{15}{4}=\dfrac{17}{2}\\\\\\\implies\dfrac{4x}{4}=\dfrac{17}{2}-\dfrac{15}{4}\\\\\\\implies\dfrac{4x}{4}=\dfrac{34-15}{4}$

$}\\\\\\\implies\dfrac{4x}{4}=\dfrac{19}{4}\\\\\\\implies4x=\dfrac{19}{4}\times4\\\\\\\implies4x=19\\\\\\\implies x=\dfrac{19}{4}\:cm$

$\\\\\\\\\Huge{\boxed{\therefore\:x=\dfrac{19}{4}\:cm}}}$

===========================

So,

 The length of rectangle

 is 19/4 cm.