Question

The perimeter of a rectangle is 17 cm. If its width is 33/4 cm, find its length​

Answer 1

Answer:

$perimeter \: ofa \: rctangle \: = 2(l + b) \\ 2(length + \: breadth) = 17 \: cm \\ 2( \frac{33}{4} + l) = 17 \: cm \\ \frac{33}{2} + 2l = 17 \: cm \: \\ \frac{33 + 4l}{2} = 17 \: cm \\ 33 + 2l = 17 \times 2 \\ 33 + 2l = 34 \\ 2l = 34 - 33 \\ 2l = 1 \\ l = \frac{1}{2} \\ lenghth = \frac{1}{2}$

Answer 2

Answer:

1/4

Step-by-step explanation:

Given,

perimeter of rectangle= 17cm

width(breadth) of rectangle= 33/4cm

therefore, perimeter of rectangle= 2 (length+breadth)

=>17= 2 ( l + 33/4)

=> 17/2= l + 33/4

=> 17/2 - 33/4 = l

l = 68-66/8

l= 2/8

length = 1/4

Thanks!!