Question

the perimeter of a rectangle is 180 metres and its length is 10 meter more than its width what is the length and width ​

Answer 1

Answer:

80

Step-by-step explanation:

p=2(l=b)(band w are like almost same)

180=2(10+W)

180/2=10+w

90=10+w

90-10=w

80=w

for confirming

p=2(10+80)

p=2(90)

p=180

its right

Answer 2

The length and width of the rectangle are 50m and 40m respectively.

Given:

The perimeter of a rectangle is 180 meters and its length is 10 meters more than its width.

To Find:

The length and width of the rectangle.

Solution:

Let us assume that the length of the rectangle is ‘x’ meters and its width is ‘y’ meters.

The perimeter of the rectangle = 2(length + width) = 2(x + y).

The perimeter is given to be 180 meters.

So, 2(x + y) = 180 or x + y = 90  ……………………..(I)

We are given that its length is 10 meters more than its width,

i.e. x = 10+y

or x – y = 10      ……………………..(II)

Adding equations (I) and (II), we get:

(x + y)+(x - y) = 90+10

2x = 100

x = 50.

Substituting the value of x in equation (I) we get,

50 + y = 90

y = 40.

Hence, the length and width of the rectangle are 50m and 40m respectively.

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