Question

The perimeter of a rectangle is 192 dm. If its length is twice its breadth, find the dimensions.​

Answer 1

Answer:

Let the length of the rectangle =l cm and breadth =b cm.

Area of the rectangle =l×b=192cm2....(1)

Perimeter of the rectangle =2(l+b)=56 cm 

⇒l+b=28  or l=28−b ....(2)

Putting the value of l in equation (1), we get

(28−b)×b=192

28b−b2=192

b2−28b+192=0

(b−16)(b−12)=0

=>b=16 or 12 cm

Substituting the value of b =16 cm in equation (1), we get

l×16=192

⇒l=12 cm

Similarly, if b =12 cm, l=16 cm. 

Dimension of the rectangle are 12 cm