The perimeter of a rectangle is 192 ft. The ratio of the length its width 7 : 5 what are the dimensions of the rectangle (A. 60 ft by 36 ft (B. 56 ft by 40 ft (C. 48 ft by 48 ft (D. 44 ft by 52 ft
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Answered by
3
2(l+b)=192
2(7z+5z)=192
24z=192
z=8
l=56
b=40
2(7z+5z)=192
24z=192
z=8
l=56
b=40
Answered by
5
SOLUTION...
Let the length and width of a rectangle be 7x and 5x respectively.
Now, perimeter of rectangle = 2 (l+b)
2 (7x +5x) = 192.
2×12x = 192
24x = 192.
x = 192/24
x = 8.
Now, length = 7×8 = 56ft.
and, width = 5×8 = 40ft.
Therefore option b.) is correct.
☆☆☆ HOPE THIS WILL HELP YOU.......
Let the length and width of a rectangle be 7x and 5x respectively.
Now, perimeter of rectangle = 2 (l+b)
2 (7x +5x) = 192.
2×12x = 192
24x = 192.
x = 192/24
x = 8.
Now, length = 7×8 = 56ft.
and, width = 5×8 = 40ft.
Therefore option b.) is correct.
☆☆☆ HOPE THIS WILL HELP YOU.......
shaneviper7:
It does but how do I do that
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