Question

The perimeter of a rectangle is 2(length) + 2(breadth).
The length of a rectangle is 3 m more than its breadth. If its perimeter is 26 m, find
the length and the breadth.​

Answer 1

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Answer 2

Given :

• The length of a rectangle is 3 m more than its breadth.
• Perimeter of the rectangle is 26 m.

To find :

• Length and breadth of the rectangle.

Solution :

Let the breadth of the rectangle be x m .

✪ The length of a rectangle is 3 m more than its breadth✪

Length = (x+3) m

We know,

${\boxed{\green{\bold{Perimeter\:of\: rectangle=2(Length+breadth)}}}}$

Perimeter = 2(x+3+x) m

→ Perimeter= 2(2x+3) m

✪Perimeter of the rectangle is 26 m.✪

According to the question,

$\sf{2(2x+3)=26}$

$\implies\sf{2x+3=\frac{26}{2}}$

$\implies\sf{2x+3=13}$

$\implies\sf{2x=13-3}$

$\implies\sf{2x=10}$

$\implies\sf{x=\frac{10}{2}}$

$\implies\sf{x=5}$

★Breadth of the rectangle= 5 m.

★Length of the rectangle = (5+3)m

= 8 m.

Therefore ,the length of the rectangle is 8 m and the breadth of the rectangle is 5 m.

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Verification :

• Length = 8 m.
• Breadth = 5 m.

Perimeter = 26 m

→ 2(8+5)=26

→ 2×13 = 26

→ 26 = 26 ( Verified )

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