Question

The perimeter of a rectangle is 20 cm. Its length is 2 cm longer than its width. What is the length and width of the rectangle?

Answer 1

Given that:

• The perimeter of a rectangle is 20 cm.
• Its length is 2 cm longer than its width.

To Find:

• What is the length and width of the rectangle?

Formula used:

• P = 2(L + B)

Where,

• P = Perimeter of a rectangle
• L = Length
• B = Width

Let us assume:

• The width of the rectangle be x cm.
• The length of the rectangle = (x + 2) cm.

According to the question.

↠ 20 = 2(x + 2 + x)

↠ 20/2 = 2x + 2

↠ 10 = 2x + 2

↠ 10 - 2 = 2x

↠ 8 = 2x

↠ 8/2 = x = 4

Hence,

• The width of the rectangle = x = 4 cm.
• The length of the rectangle = (x + 2) = (4 + 2) = 6 cm.

Answer 2

Given :-

The perimeter of a rectangle is 20 cm. Its length is 2 cm longer than its width.

To Find :-

Length

Width

Solution :-

I'm solving this question by two methods.

Method 1

Let

length = x

breadth = y

Then,

x = y + 2 (i)

Perimeter = 2(l + b)

20 = 2(x + y)

20/2 = x + y

10 = x + y

10 - y = x (ii)

SInce, both equation are equal

y + 2 = 10 - y

y + y = 10 - 2

2y = 8

y = 8/2

y = 4

10 - y = x

10 - 4 = x

6 = x

Hence

Length = x = 6 cm

Breadth = y = 4 cm

Method 2

Let

Breadth = x

Length = x + 2

Perimeter = 2(l + b)

20 = 2(x + x + 2)

20/2 = 2x + 2

10 = 2x + 2

10 - 2 = 2x

8 = 2x

8/2 = x

4 = x

Length = x + 2 = 4 + 2 = 6 cm

Breadth = x = 4 cm