Question

the perimeter of a rectangle is 20 metere its length is 2 metere greater than its breadth find its length and breadth​

Answer 1

Answer:

P=20m=l+b

l=b+2

Therefore, by substitution, we get,

(b+2)+b=20

2b+2=20

2b=18

b=9m

l=b+2=11m

Answer 2

Hello dear!❤

Solution:

Given, Perimeter = 20 m

Let breadth be x and length be x+2

A/Q

$perimeter = 2(l + b)$

$20m = 2(2 + x + x)$

$20m = 4 + 2x + 2x$

$20m = 4 + 4x$

$4x = 20 - 4$

$4x = 16$

$x = \frac{16}{4} = 4$

Length = 4m

Breadth = x+2 = 4+2 = 6m

Hope this helps

@adiba31☺❤