The perimeter of a rectangle is 200 m while the difference between the length and the breadth is 50 m. Find the area of the rectangle
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perimeter of the rectangle = 200 m
2(l+b)=200
l+b=100.......(1)
difference of length and breadth is 50 m
l-b=50 .......(2)
solve by equation (1) &(2)
length l=75 m
breadth b=25 m
Area of the rectangle A= l x b
=75 x 25
=1875 sq.m
2(l+b)=200
l+b=100.......(1)
difference of length and breadth is 50 m
l-b=50 .......(2)
solve by equation (1) &(2)
length l=75 m
breadth b=25 m
Area of the rectangle A= l x b
=75 x 25
=1875 sq.m
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